Base | Representation |
---|---|
bin | 1100000000100001011101… |
… | …0110000100101001111111 |
3 | 1201202012120012202001101102 |
4 | 3000020113112010221333 |
5 | 3212304443002130421 |
6 | 44025232523203315 |
7 | 2531615435620163 |
oct | 300102726045177 |
9 | 51665505661342 |
10 | 13203121130111 |
11 | 4230459745170 |
12 | 1592a2a67653b |
13 | 74a0837c0233 |
14 | 33906a840ca3 |
15 | 17d69bb2a60b |
hex | c0217584a7f |
13203121130111 has 4 divisors (see below), whose sum is σ = 14403404869224. Its totient is φ = 12002837391000.
The previous prime is 13203121130093. The next prime is 13203121130119. The reversal of 13203121130111 is 11103112130231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13203121130111 - 230 = 13202047388287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13203121130119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600141869540 + ... + 600141869561.
It is an arithmetic number, because the mean of its divisors is an integer number (3600851217306).
Almost surely, 213203121130111 is an apocalyptic number.
13203121130111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13203121130111 is a deficient number, since it is larger than the sum of its proper divisors (1200283739113).
13203121130111 is a wasteful number, since it uses less digits than its factorization.
13203121130111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1200283739112.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 13203121130111 its reverse (11103112130231), we get a palindrome (24306233260342).
The spelling of 13203121130111 in words is "thirteen trillion, two hundred three billion, one hundred twenty-one million, one hundred thirty thousand, one hundred eleven".
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