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132031421041 = 1323441576659
BaseRepresentation
bin111101011110110101…
…1111001101001110001
3110121210111102010102011
41322331223321221301
54130400020433131
6140353203322521
712352601363452
oct1727553715161
9417714363364
10132031421041
1150aa33278a3
1221709080441
13c5b1a00910
1465671c3129
15367b3810b1
hex1ebdaf9a71

132031421041 has 8 divisors (see below), whose sum is σ = 148369757760. Its totient is φ = 116576237712.

The previous prime is 132031421029. The next prime is 132031421047. The reversal of 132031421041 is 140124130231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132031421041 - 215 = 132031388273 is a prime.

It is a super-2 number, since 2×1320314210412 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132031421047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 220788031 + ... + 220788628.

It is an arithmetic number, because the mean of its divisors is an integer number (18546219720).

Almost surely, 2132031421041 is an apocalyptic number.

It is an amenable number.

132031421041 is a deficient number, since it is larger than the sum of its proper divisors (16338336719).

132031421041 is a wasteful number, since it uses less digits than its factorization.

132031421041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 441576695.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 132031421041 its reverse (140124130231), we get a palindrome (272155551272).

The spelling of 132031421041 in words is "one hundred thirty-two billion, thirty-one million, four hundred twenty-one thousand, forty-one".

Divisors: 1 13 23 299 441576659 5740496567 10156263157 132031421041