Base | Representation |
---|---|
bin | 11110000001010011111101… |
… | …101010011101001001100111 |
3 | 122022111002111202120202121212 |
4 | 132001103331222131021213 |
5 | 114301201103403203020 |
6 | 1144450242410302035 |
7 | 36544651621440626 |
oct | 3601237552351147 |
9 | 568432452522555 |
10 | 132031550444135 |
11 | 390842a2196731 |
12 | 1298472312791b |
13 | 58896a24861c4 |
14 | 248650ad6b6bd |
15 | 103e69c360cc5 |
hex | 7814fda9d267 |
132031550444135 has 8 divisors (see below), whose sum is σ = 158596775143296. Its totient is φ = 105519297281760.
The previous prime is 132031550444089. The next prime is 132031550444137. The reversal of 132031550444135 is 531444055130231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132031550444135 - 216 = 132031550378599 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132031550444092 and 132031550444101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132031550444137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13242878711 + ... + 13242888680.
It is an arithmetic number, because the mean of its divisors is an integer number (19824596892912).
Almost surely, 2132031550444135 is an apocalyptic number.
132031550444135 is a deficient number, since it is larger than the sum of its proper divisors (26565224699161).
132031550444135 is an equidigital number, since it uses as much as digits as its factorization.
132031550444135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26485768393.
The product of its (nonzero) digits is 432000, while the sum is 41.
The spelling of 132031550444135 in words is "one hundred thirty-two trillion, thirty-one billion, five hundred fifty million, four hundred forty-four thousand, one hundred thirty-five".
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