1320322320131 has 4 divisors (see below), whose sum is σ = 1342700664600. Its totient is φ = 1297943975664.

The previous prime is 1320322320101. The next prime is 1320322320133. The reversal of 1320322320131 is 1310232230231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320322320131 is a prime.

It is a super-2 number, since 2×1320322320131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320322320097 and 1320322320106.

It is not an unprimeable number, because it can be changed into a prime (1320322320133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11189172146 + ... + 11189172263.

It is an arithmetic number, because the mean of its divisors is an integer number (335675166150).

Almost surely, 2^{1320322320131} is an apocalyptic number.

1320322320131 is a deficient number, since it is larger than the sum of its proper divisors (22378344469).

1320322320131 is an equidigital number, since it uses as much as digits as its factorization.

1320322320131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22378344468.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1320322320131 its reverse (1310232230231), we get a palindrome (2630554550362).

The spelling of 1320322320131 in words is "one trillion, three hundred twenty billion, three hundred twenty-two million, three hundred twenty thousand, one hundred thirty-one".