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13203231232153 is a prime number
BaseRepresentation
bin1100000000100001110111…
…1010000101000010011001
31201202012211212220210222211
43000020131322011002121
53212310204143412103
644025251455115121
72531621243515324
oct300103572050231
951665755823884
1013203231232153
114230505906496
121592a5b512aa1
1374a0a055cb81
1433907b3017bb
1517d6a662836d
hexc021de85099

13203231232153 has 2 divisors, whose sum is σ = 13203231232154. Its totient is φ = 13203231232152.

The previous prime is 13203231232151. The next prime is 13203231232187. The reversal of 13203231232153 is 35123213230231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7209611645184 + 5993619586969 = 2685072^2 + 2448187^2 .

It is a cyclic number.

It is not a de Polignac number, because 13203231232153 - 21 = 13203231232151 is a prime.

Together with 13203231232151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13203231232151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6601615616076 + 6601615616077.

It is an arithmetic number, because the mean of its divisors is an integer number (6601615616077).

Almost surely, 213203231232153 is an apocalyptic number.

It is an amenable number.

13203231232153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13203231232153 is an equidigital number, since it uses as much as digits as its factorization.

13203231232153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 31.

Adding to 13203231232153 its reverse (35123213230231), we get a palindrome (48326444462384).

The spelling of 13203231232153 in words is "thirteen trillion, two hundred three billion, two hundred thirty-one million, two hundred thirty-two thousand, one hundred fifty-three".