132032511244340 has 192 divisors, whose sum is σ = 319121678991360. Its totient is φ = 44949065978880.

The previous prime is 132032511244241. The next prime is 132032511244349. The reversal of 132032511244340 is 43442115230231.

It is a Harshad number since it is a multiple of its sum of digits (35).

It is a self number, because there is not a number n which added to its sum of digits gives 132032511244340.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132032511244349) by changing a digit.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 39780809201 + ... + 39780812519.

It is an arithmetic number, because the mean of its divisors is an integer number (1662092078080).

Almost surely, 2^{132032511244340} is an apocalyptic number.

132032511244340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132032511244340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (159560839495680).

132032511244340 is an abundant number, since it is smaller than the sum of its proper divisors (187089167747020).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132032511244340 is a wasteful number, since it uses less digits than its factorization.

132032511244340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6830 (or 6828 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 132032511244340 its reverse (43442115230231), we get a palindrome (175474626474571).

The spelling of 132032511244340 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred eleven million, two hundred forty-four thousand, three hundred forty".