13203534031 has 4 divisors (see below), whose sum is σ = 13777600752. Its totient is φ = 12629467312.

The previous prime is 13203534023. The next prime is 13203534037. The reversal of 13203534031 is 13043530231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13203534031 - 2³ = 13203534023 is a prime.

It is a super-2 number, since 2×13203534031² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13203533987 and 13203534005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13203534037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 287033326 + ... + 287033371.

It is an arithmetic number, because the mean of its divisors is an integer number (3444400188).

Almost surely, 2^13203534031 is an apocalyptic number.

13203534031 is a deficient number, since it is larger than the sum of its proper divisors (574066721).

13203534031 is an equidigital number, since it uses as much as digits as its factorization.

13203534031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 574066720.

The product of its (nonzero) digits is 3240, while the sum is 25.

The spelling of 13203534031 in words is "thirteen billion, two hundred three million, five hundred thirty-four thousand, thirty-one".