Base | Representation |
---|---|
bin | 110010010111… |
… | …101010010101 |
3 | 220211211122101 |
4 | 302113222111 |
5 | 11340012432 |
6 | 1151002101 |
7 | 220142653 |
oct | 62275225 |
9 | 26754571 |
10 | 13204117 |
11 | 74a94a3 |
12 | 4509331 |
13 | 29740b4 |
14 | 1a79dd3 |
15 | 125c4e7 |
hex | c97a95 |
13204117 has 2 divisors, whose sum is σ = 13204118. Its totient is φ = 13204116.
The previous prime is 13204097. The next prime is 13204123. The reversal of 13204117 is 71140231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11329956 + 1874161 = 3366^2 + 1369^2 .
It is a cyclic number.
It is not a de Polignac number, because 13204117 - 215 = 13171349 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13204094 and 13204103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13204157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602058 + 6602059.
It is an arithmetic number, because the mean of its divisors is an integer number (6602059).
Almost surely, 213204117 is an apocalyptic number.
It is an amenable number.
13204117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204117 is an equidigital number, since it uses as much as digits as its factorization.
13204117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 19.
The square root of 13204117 is about 3633.7469642230. The cubic root of 13204117 is about 236.3577178319.
Adding to 13204117 its reverse (71140231), we get a palindrome (84344348).
The spelling of 13204117 in words is "thirteen million, two hundred four thousand, one hundred seventeen".
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