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13204214343 = 324393341993
BaseRepresentation
bin11000100110000100…
…00101001001000111
31021002020001120212200
430103002011021013
5204020234324333
610022124045543
7645132653505
oct142302051107
937066046780
1013204214343
115666486741
1226860938b3
1313257a32a8
148d3927675
1552433ec13
hex313085247

13204214343 has 12 divisors (see below), whose sum is σ = 19116205680. Its totient is φ = 8782754976.

The previous prime is 13204214333. The next prime is 13204214389. The reversal of 13204214343 is 34341240231.

13204214343 is a `hidden beast` number, since 1 + 3 + 204 + 21 + 434 + 3 = 666.

It is not a de Polignac number, because 13204214343 - 212 = 13204210247 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13204214333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1667046 + ... + 1674947.

It is an arithmetic number, because the mean of its divisors is an integer number (1593017140).

Almost surely, 213204214343 is an apocalyptic number.

13204214343 is a deficient number, since it is larger than the sum of its proper divisors (5911991337).

13204214343 is a wasteful number, since it uses less digits than its factorization.

13204214343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3342438 (or 3342435 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 13204214343 its reverse (34341240231), we get a palindrome (47545454574).

The spelling of 13204214343 in words is "thirteen billion, two hundred four million, two hundred fourteen thousand, three hundred forty-three".

Divisors: 1 3 9 439 1317 3951 3341993 10025979 30077937 1467134927 4401404781 13204214343