13204340353145 has 4 divisors (see below), whose sum is σ = 15845208423780. Its totient is φ = 10563472282512.

The previous prime is 13204340353129. The next prime is 13204340353151. The reversal of 13204340353145 is 54135304340231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1391295739024 + 11813044614121 = 1179532^2 + 3437011^2 .

It is a cyclic number.

It is not a de Polignac number, because 13204340353145 - 2⁴ = 13204340353129 is a prime.

It is a super-2 number, since 2×13204340353145² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13204340353099 and 13204340353108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320434035310 + ... + 1320434035319.

It is an arithmetic number, because the mean of its divisors is an integer number (3961302105945).

Almost surely, 2^{13204340353145} is an apocalyptic number.

It is an amenable number.

13204340353145 is a deficient number, since it is larger than the sum of its proper divisors (2640868070635).

13204340353145 is an equidigital number, since it uses as much as digits as its factorization.

13204340353145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2640868070634.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 13204340353145 its reverse (54135304340231), we get a palindrome (67339644693376).

The spelling of 13204340353145 in words is "thirteen trillion, two hundred four billion, three hundred forty million, three hundred fifty-three thousand, one hundred forty-five".