Search a number
-
+
132044131310999 is a prime number
BaseRepresentation
bin11110000001011111101011…
…100010101001110110010111
3122022112021222112201000111212
4132001133223202221312113
5114301402340103422444
61144500123030052035
736545605445155025
oct3601375342516627
9568467875630455
10132044131310999
1139089668818166
12129870544aa01b
13588a928a7791b
142486d81b91715
15103eb86ac019e
hex7817eb8a9d97

132044131310999 has 2 divisors, whose sum is σ = 132044131311000. Its totient is φ = 132044131310998.

The previous prime is 132044131310947. The next prime is 132044131311023. The reversal of 132044131310999 is 999013131440231.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (999013131440231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132044131310999 - 216 = 132044131245463 is a prime.

It is a super-2 number, since 2×1320441313109992 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132044131310909) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022065655499 + 66022065655500.

It is an arithmetic number, because the mean of its divisors is an integer number (66022065655500).

Almost surely, 2132044131310999 is an apocalyptic number.

132044131310999 is a deficient number, since it is larger than the sum of its proper divisors (1).

132044131310999 is an equidigital number, since it uses as much as digits as its factorization.

132044131310999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 629856, while the sum is 50.

The spelling of 132044131310999 in words is "one hundred thirty-two trillion, forty-four billion, one hundred thirty-one million, three hundred ten thousand, nine hundred ninety-nine".