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132052439928917 is a prime number
BaseRepresentation
bin11110000001100111011010…
…110001100001000001010101
3122022120002102120211112121102
4132001213122301201001111
5114302021344110211132
61144504015312355445
736546321364226624
oct3601473261410125
9568502376745542
10132052439928917
1139092141815842
1212988792b45b85
13588b6512152a1
14248752d4336bb
15103eec122cc62
hex7819dac61055

132052439928917 has 2 divisors, whose sum is σ = 132052439928918. Its totient is φ = 132052439928916.

The previous prime is 132052439928881. The next prime is 132052439928953. The reversal of 132052439928917 is 719829934250231.

It is a balanced prime because it is at equal distance from previous prime (132052439928881) and next prime (132052439928953).

It can be written as a sum of positive squares in only one way, i.e., 128799210852676 + 3253229076241 = 11348974^2 + 1803671^2 .

It is a cyclic number.

It is not a de Polignac number, because 132052439928917 - 26 = 132052439928853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132052439928967) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026219964458 + 66026219964459.

It is an arithmetic number, because the mean of its divisors is an integer number (66026219964459).

Almost surely, 2132052439928917 is an apocalyptic number.

It is an amenable number.

132052439928917 is a deficient number, since it is larger than the sum of its proper divisors (1).

132052439928917 is an equidigital number, since it uses as much as digits as its factorization.

132052439928917 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58786560, while the sum is 65.

The spelling of 132052439928917 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred thirty-nine million, nine hundred twenty-eight thousand, nine hundred seventeen".