Base | Representation |
---|---|
bin | 111101011111100010… |
… | …1101001110101000101 |
3 | 110121212010200110222001 |
4 | 1322333011221311011 |
5 | 4130422031333224 |
6 | 140355403505301 |
7 | 12353305355602 |
oct | 1727705516505 |
9 | 417763613861 |
10 | 132054949189 |
11 | 51005637949 |
12 | 21714b28231 |
13 | c5b684abb7 |
14 | 656a3896a9 |
15 | 367d47c544 |
hex | 1ebf169d45 |
132054949189 has 2 divisors, whose sum is σ = 132054949190. Its totient is φ = 132054949188.
The previous prime is 132054949181. The next prime is 132054949193. The reversal of 132054949189 is 981949450231.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 67927996900 + 64126952289 = 260630^2 + 253233^2 .
It is a cyclic number.
It is not a de Polignac number, because 132054949189 - 23 = 132054949181 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132054949181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66027474594 + 66027474595.
It is an arithmetic number, because the mean of its divisors is an integer number (66027474595).
Almost surely, 2132054949189 is an apocalyptic number.
It is an amenable number.
132054949189 is a deficient number, since it is larger than the sum of its proper divisors (1).
132054949189 is an equidigital number, since it uses as much as digits as its factorization.
132054949189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2799360, while the sum is 55.
The spelling of 132054949189 in words is "one hundred thirty-two billion, fifty-four million, nine hundred forty-nine thousand, one hundred eighty-nine".
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