Base | Representation |
---|---|
bin | 11110000001111110001111… |
… | …010010011001101010100111 |
3 | 122022122102200021012222220121 |
4 | 132001332033102121222213 |
5 | 114302422034440104103 |
6 | 1144523150552342411 |
7 | 36551146531302361 |
oct | 3601761722315247 |
9 | 568572607188817 |
10 | 132076943284903 |
11 | 390a1576277871 |
12 | 129914910a4a07 |
13 | 5890a578a00b6 |
14 | 24887b5859d31 |
15 | 10409574eb6bd |
hex | 781f8f499aa7 |
132076943284903 has 2 divisors, whose sum is σ = 132076943284904. Its totient is φ = 132076943284902.
The previous prime is 132076943284877. The next prime is 132076943284939. The reversal of 132076943284903 is 309482349670231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132076943284903 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132076943284943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66038471642451 + 66038471642452.
It is an arithmetic number, because the mean of its divisors is an integer number (66038471642452).
Almost surely, 2132076943284903 is an apocalyptic number.
132076943284903 is a deficient number, since it is larger than the sum of its proper divisors (1).
132076943284903 is an equidigital number, since it uses as much as digits as its factorization.
132076943284903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47029248, while the sum is 61.
The spelling of 132076943284903 in words is "one hundred thirty-two trillion, seventy-six billion, nine hundred forty-three million, two hundred eighty-four thousand, nine hundred three".
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