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132100817353 = 563234637331
BaseRepresentation
bin111101100000111010…
…0101000000111001001
3110121222022222211020221
41323001310220013021
54131020302123403
6140404122550041
712354403264201
oct1730164500711
9417868884227
10132100817353
115102951631a
1221728368321
13c5c31ba71b
1465724c9401
1536824dcdbd
hex1ec1d281c9

132100817353 has 4 divisors (see below), whose sum is σ = 132335455248. Its totient is φ = 131866179460.

The previous prime is 132100817351. The next prime is 132100817413. The reversal of 132100817353 is 353718001231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132100817353 - 21 = 132100817351 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132100817351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117318103 + ... + 117319228.

It is an arithmetic number, because the mean of its divisors is an integer number (33083863812).

Almost surely, 2132100817353 is an apocalyptic number.

It is an amenable number.

132100817353 is a deficient number, since it is larger than the sum of its proper divisors (234637895).

132100817353 is an equidigital number, since it uses as much as digits as its factorization.

132100817353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 234637894.

The product of its (nonzero) digits is 15120, while the sum is 34.

Adding to 132100817353 its reverse (353718001231), we get a palindrome (485818818584).

The spelling of 132100817353 in words is "one hundred thirty-two billion, one hundred million, eight hundred seventeen thousand, three hundred fifty-three".

Divisors: 1 563 234637331 132100817353