Base | Representation |
---|---|
bin | 1100000000111100000000… |
… | …0111100100010100100011 |
3 | 1201202212221212112111012222 |
4 | 3000033000013210110203 |
5 | 3212414041344110301 |
6 | 44032412021141255 |
7 | 2532260152162004 |
oct | 300170007442443 |
9 | 51685855474188 |
10 | 13210247644451 |
11 | 423348644a940 |
12 | 159429925a82b |
13 | 74a94b091220 |
14 | 3395450d11ab |
15 | 17d9675d531b |
hex | c03c01e4523 |
13210247644451 has 32 divisors (see below), whose sum is σ = 16245590473728. Its totient is φ = 10570092762240.
The previous prime is 13210247644369. The next prime is 13210247644481. The reversal of 13210247644451 is 15444674201231.
It is a de Polignac number, because none of the positive numbers 2k-13210247644451 is a prime.
It is a super-2 number, since 2×132102476444512 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13210247644481) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5292551 + ... + 7377776.
It is an arithmetic number, because the mean of its divisors is an integer number (507674702304).
Almost surely, 213210247644451 is an apocalyptic number.
13210247644451 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13210247644451 is a deficient number, since it is larger than the sum of its proper divisors (3035342829277).
13210247644451 is a wasteful number, since it uses less digits than its factorization.
13210247644451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12670691.
The product of its (nonzero) digits is 645120, while the sum is 44.
The spelling of 13210247644451 in words is "thirteen trillion, two hundred ten billion, two hundred forty-seven million, six hundred forty-four thousand, four hundred fifty-one".
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