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132104143543 = 343338480671
BaseRepresentation
bin111101100001000000…
…1010100001010110111
3110121222120020210221011
41323002001110022313
54131022130043133
6140404322133051
712354443456431
oct1730201241267
9417876223834
10132104143543
1151030388339
12217294b1187
13c5c3ab3698
146572b13651
1536829486cd
hex1ec20542b7

132104143543 has 4 divisors (see below), whose sum is σ = 132142627648. Its totient is φ = 132065659440.

The previous prime is 132104143537. The next prime is 132104143553. The reversal of 132104143543 is 345341401231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 345341401231 = 3111140045201.

It is a cyclic number.

It is not a de Polignac number, because 132104143543 - 25 = 132104143511 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132104143553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19236903 + ... + 19243768.

It is an arithmetic number, because the mean of its divisors is an integer number (33035656912).

Almost surely, 2132104143543 is an apocalyptic number.

132104143543 is a deficient number, since it is larger than the sum of its proper divisors (38484105).

132104143543 is an equidigital number, since it uses as much as digits as its factorization.

132104143543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38484104.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 132104143543 its reverse (345341401231), we get a palindrome (477445544774).

The spelling of 132104143543 in words is "one hundred thirty-two billion, one hundred four million, one hundred forty-three thousand, five hundred forty-three".

Divisors: 1 3433 38480671 132104143543