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132104434544231 is a prime number
BaseRepresentation
bin11110000010010111110101…
…111001001110111001100111
3122022202001122011212200001112
4132002113311321032321213
5114303344340220403411
61144543534525415235
736553142016166442
oct3602276571167147
9568661564780045
10132104434544231
11391021a33878a6
1212996883a0a51b
135893519295456
142489c62a1a659
151041515c6eb8b
hex7825f5e4ee67

132104434544231 has 2 divisors, whose sum is σ = 132104434544232. Its totient is φ = 132104434544230.

The previous prime is 132104434544177. The next prime is 132104434544233. The reversal of 132104434544231 is 132445434401231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132104434544231 - 214 = 132104434527847 is a prime.

It is a super-2 number, since 2×1321044345442312 (a number of 29 digits) contains 22 as substring.

Together with 132104434544233, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132104434544233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052217272115 + 66052217272116.

It is an arithmetic number, because the mean of its divisors is an integer number (66052217272116).

Almost surely, 2132104434544231 is an apocalyptic number.

132104434544231 is a deficient number, since it is larger than the sum of its proper divisors (1).

132104434544231 is an equidigital number, since it uses as much as digits as its factorization.

132104434544231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 552960, while the sum is 41.

Adding to 132104434544231 its reverse (132445434401231), we get a palindrome (264549868945462).

The spelling of 132104434544231 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred thirty-four million, five hundred forty-four thousand, two hundred thirty-one".