Base | Representation |
---|---|
bin | 11110000010011101000001… |
… | …101100011010111010111111 |
3 | 122022202121000010120011102201 |
4 | 132002131001230122322333 |
5 | 114303442240303040221 |
6 | 1144550255142532331 |
7 | 36553426662154621 |
oct | 3602350154327277 |
9 | 568677003504381 |
10 | 132110001221311 |
11 | 3910459a652773 |
12 | 129979781370a7 |
13 | 5893bc5653309 |
14 | 248a23006cc11 |
15 | 104173e810891 |
hex | 782741b1aebf |
132110001221311 has 2 divisors, whose sum is σ = 132110001221312. Its totient is φ = 132110001221310.
The previous prime is 132110001221243. The next prime is 132110001221321. The reversal of 132110001221311 is 113122100011231.
It is a strong prime.
It is an emirp because it is prime and its reverse (113122100011231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132110001221311 - 211 = 132110001219263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132110001221321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055000610655 + 66055000610656.
It is an arithmetic number, because the mean of its divisors is an integer number (66055000610656).
Almost surely, 2132110001221311 is an apocalyptic number.
132110001221311 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110001221311 is an equidigital number, since it uses as much as digits as its factorization.
132110001221311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 132110001221311 its reverse (113122100011231), we get a palindrome (245232101232542).
The spelling of 132110001221311 in words is "one hundred thirty-two trillion, one hundred ten billion, one million, two hundred twenty-one thousand, three hundred eleven".
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