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13211003053 = 103451127703
BaseRepresentation
bin11000100110110111…
…11110100010101101
31021002200211111020101
430103123332202231
5204024004044203
610022525351101
7645244446613
oct142333764255
937080744211
1013211003053
11566a2a3146
122688408491
13132700c291
148d47b36b3
15524c3141d
hex3136fe8ad

13211003053 has 4 divisors (see below), whose sum is σ = 13211234208. Its totient is φ = 13210771900.

The previous prime is 13211003021. The next prime is 13211003063. The reversal of 13211003053 is 35030011231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13211003053 - 25 = 13211003021 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13211003053.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13211003063) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39600 + ... + 167302.

It is an arithmetic number, because the mean of its divisors is an integer number (3302808552).

Almost surely, 213211003053 is an apocalyptic number.

It is an amenable number.

13211003053 is a deficient number, since it is larger than the sum of its proper divisors (231155).

13211003053 is a wasteful number, since it uses less digits than its factorization.

13211003053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231154.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 13211003053 its reverse (35030011231), we get a palindrome (48241014284).

The spelling of 13211003053 in words is "thirteen billion, two hundred eleven million, three thousand, fifty-three".

Divisors: 1 103451 127703 13211003053