Base | Representation |
---|---|
bin | 11000100110111000… |
… | …01011000010100101 |
3 | 1021002200221002110101 |
4 | 30103130023002211 |
5 | 204024012213440 |
6 | 10022530424101 |
7 | 645245052064 |
oct | 142334130245 |
9 | 37080832411 |
10 | 13211054245 |
11 | 566a328654 |
12 | 2688432031 |
13 | 132702967c |
14 | 8d47c81db |
15 | 524c4169a |
hex | 31370b0a5 |
13211054245 has 4 divisors (see below), whose sum is σ = 15853265100. Its totient is φ = 10568843392.
The previous prime is 13211054243. The next prime is 13211054273. The reversal of 13211054245 is 54245011231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7520011524 + 5691042721 = 86718^2 + 75439^2 .
It is a cyclic number.
It is not a de Polignac number, because 13211054245 - 21 = 13211054243 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13211054243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1321105420 + ... + 1321105429.
It is an arithmetic number, because the mean of its divisors is an integer number (3963316275).
Almost surely, 213211054245 is an apocalyptic number.
It is an amenable number.
13211054245 is a deficient number, since it is larger than the sum of its proper divisors (2642210855).
13211054245 is an equidigital number, since it uses as much as digits as its factorization.
13211054245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2642210854.
The product of its (nonzero) digits is 4800, while the sum is 28.
Adding to 13211054245 its reverse (54245011231), we get a palindrome (67456065476).
It can be divided in two parts, 132110 and 54245, that added together give a triangular number (186355 = T610).
The spelling of 13211054245 in words is "thirteen billion, two hundred eleven million, fifty-four thousand, two hundred forty-five".
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