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1321106552301 = 3440368850767
BaseRepresentation
bin10011001110011000000…
…101100011010111101101
311200022000012001101212110
4103032120011203113231
5133121111234133201
62450524042154233
7164306152261314
oct23163005432755
94608005041773
101321106552301
1146a307231348
12194057ab2979
139776cb08243
1447d287d727b
1524571dbd6d6
hex133981635ed

1321106552301 has 4 divisors (see below), whose sum is σ = 1761475403072. Its totient is φ = 880737701532.

The previous prime is 1321106552221. The next prime is 1321106552317. The reversal of 1321106552301 is 1032556011231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1321106552301 - 218 = 1321106290157 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1321106552341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220184425381 + ... + 220184425386.

It is an arithmetic number, because the mean of its divisors is an integer number (440368850768).

Almost surely, 21321106552301 is an apocalyptic number.

It is an amenable number.

1321106552301 is a deficient number, since it is larger than the sum of its proper divisors (440368850771).

1321106552301 is an equidigital number, since it uses as much as digits as its factorization.

1321106552301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440368850770.

The product of its (nonzero) digits is 5400, while the sum is 30.

The spelling of 1321106552301 in words is "one trillion, three hundred twenty-one billion, one hundred six million, five hundred fifty-two thousand, three hundred one".

Divisors: 1 3 440368850767 1321106552301