1321133112133 has 4 divisors (see below), whose sum is σ = 1321290043360. Its totient is φ = 1320976180908.

The previous prime is 1321133112049. The next prime is 1321133112137. The reversal of 1321133112133 is 3312113311231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1321133112133 - 2⁹ = 1321133111621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1321133112098 and 1321133112107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1321133112137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 78452985 + ... + 78469822.

It is an arithmetic number, because the mean of its divisors is an integer number (330322510840).

Almost surely, 2^{1321133112133} is an apocalyptic number.

It is an amenable number.

1321133112133 is a deficient number, since it is larger than the sum of its proper divisors (156931227).

1321133112133 is an equidigital number, since it uses as much as digits as its factorization.

1321133112133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156931226.

The product of its digits is 972, while the sum is 25.

Adding to 1321133112133 its reverse (3312113311231), we get a palindrome (4633246423364).

The spelling of 1321133112133 in words is "one trillion, three hundred twenty-one billion, one hundred thirty-three million, one hundred twelve thousand, one hundred thirty-three".