Search a number
-
+
132113320140 = 22352201888669
BaseRepresentation
bin111101100001010010…
…0010100100011001100
3110122000012112000212010
41323002210110203030
54131032002221030
6140405250541220
712354614456364
oct1730244244314
9418005460763
10132113320140
11510355858aa
1221730597810
13c5c5977519
1465740219a4
15368365c6b0
hex1ec29148cc

132113320140 has 24 divisors (see below), whose sum is σ = 369917296560. Its totient is φ = 35230218688.

The previous prime is 132113320123. The next prime is 132113320147. The reversal of 132113320140 is 41023311231.

It is not an unprimeable number, because it can be changed into a prime (132113320147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1100944275 + ... + 1100944394.

It is an arithmetic number, because the mean of its divisors is an integer number (15413220690).

Almost surely, 2132113320140 is an apocalyptic number.

132113320140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132113320140 is an abundant number, since it is smaller than the sum of its proper divisors (237803976420).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132113320140 is a wasteful number, since it uses less digits than its factorization.

132113320140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2201888681 (or 2201888679 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 132113320140 its reverse (41023311231), we get a palindrome (173136631371).

The spelling of 132113320140 in words is "one hundred thirty-two billion, one hundred thirteen million, three hundred twenty thousand, one hundred forty".

Divisors: 1 2 3 4 5 6 10 12 15 20 30 60 2201888669 4403777338 6605666007 8807554676 11009443345 13211332014 22018886690 26422664028 33028330035 44037773380 66056660070 132113320140