132113432420143 has 2 divisors, whose sum is σ = 132113432420144. Its totient is φ = 132113432420142.

The previous prime is 132113432420107. The next prime is 132113432420201. The reversal of 132113432420143 is 341024234311231.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132113432420143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132113432420099 and 132113432420108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132113432420843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66056716210071 + 66056716210072.

It is an arithmetic number, because the mean of its divisors is an integer number (66056716210072).

Almost surely, 2^{132113432420143} is an apocalyptic number.

132113432420143 is a deficient number, since it is larger than the sum of its proper divisors (1).

132113432420143 is an equidigital number, since it uses as much as digits as its factorization.

132113432420143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 132113432420143 its reverse (341024234311231), we get a palindrome (473137666731374).

The spelling of 132113432420143 in words is "one hundred thirty-two trillion, one hundred thirteen billion, four hundred thirty-two million, four hundred twenty thousand, one hundred forty-three".