Base | Representation |
---|---|
bin | 11110000010100000111000… |
… | …000010111010100011111010 |
3 | 122022202222200011200222122110 |
4 | 132002200320002322203322 |
5 | 114304024221341010320 |
6 | 1144552221225233150 |
7 | 36553634256650340 |
oct | 3602407002724372 |
9 | 568688604628573 |
10 | 132114134313210 |
11 | 3910632067a8a5 |
12 | 129987303327b6 |
13 | 5894403a0391a |
14 | 248a502d49990 |
15 | 10418d25c55e0 |
hex | 7828380ba8fa |
132114134313210 has 32 divisors (see below), whose sum is σ = 362370196973952. Its totient is φ = 30197516414400.
The previous prime is 132114134313157. The next prime is 132114134313233. The reversal of 132114134313210 is 12313431411231.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 314557462441 + ... + 314557462860.
It is an arithmetic number, because the mean of its divisors is an integer number (11324068655436).
Almost surely, 2132114134313210 is an apocalyptic number.
132114134313210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132114134313210 is an abundant number, since it is smaller than the sum of its proper divisors (230256062660742).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132114134313210 is a wasteful number, since it uses less digits than its factorization.
132114134313210 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 629114925318.
The product of its (nonzero) digits is 5184, while the sum is 30.
Adding to 132114134313210 its reverse (12313431411231), we get a palindrome (144427565724441).
The spelling of 132114134313210 in words is "one hundred thirty-two trillion, one hundred fourteen billion, one hundred thirty-four million, three hundred thirteen thousand, two hundred ten".
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