132114134343221 has 2 divisors, whose sum is σ = 132114134343222. Its totient is φ = 132114134343220.

The previous prime is 132114134343203. The next prime is 132114134343223. The reversal of 132114134343221 is 122343431411231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109802105822500 + 22312028520721 = 10478650^2 + 4723561^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132114134343221 is a prime.

Together with 132114134343223, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132114134343223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057067171610 + 66057067171611.

It is an arithmetic number, because the mean of its divisors is an integer number (66057067171611).

Almost surely, 2^{132114134343221} is an apocalyptic number.

It is an amenable number.

132114134343221 is a deficient number, since it is larger than the sum of its proper divisors (1).

132114134343221 is an equidigital number, since it uses as much as digits as its factorization.

132114134343221 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 35.

Adding to 132114134343221 its reverse (122343431411231), we get a palindrome (254457565754452).

The spelling of 132114134343221 in words is "one hundred thirty-two trillion, one hundred fourteen billion, one hundred thirty-four million, three hundred forty-three thousand, two hundred twenty-one".