Base | Representation |
---|---|
bin | 11110000010100001000010… |
… | …000111100101110111001110 |
3 | 122022210000002221200222110100 |
4 | 132002201002013211313032 |
5 | 114304030043121430220 |
6 | 1144552250103351530 |
7 | 36553641411264225 |
oct | 3602410207456716 |
9 | 568700087628410 |
10 | 132114303311310 |
11 | 391063a8008651 |
12 | 12998778a525a6 |
13 | 589442ca24bb8 |
14 | 248a51b57bcbc |
15 | 10418e2358d90 |
hex | 7828421e5dce |
132114303311310 has 192 divisors, whose sum is σ = 359884526376960. Its totient is φ = 33562354129920.
The previous prime is 132114303311297. The next prime is 132114303311321. The reversal of 132114303311310 is 13113303411231.
132114303311310 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 1 + 4 + 30 + 3 + 311 + 310 = 666.
It is a super-2 number, since 2×1321143033113102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 669312411 + ... + 669509769.
It is an arithmetic number, because the mean of its divisors is an integer number (1874398574880).
Almost surely, 2132114303311310 is an apocalyptic number.
132114303311310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 132114303311310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (179942263188480).
132114303311310 is an abundant number, since it is smaller than the sum of its proper divisors (227770223065650).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132114303311310 is a wasteful number, since it uses less digits than its factorization.
132114303311310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198703 (or 198700 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 27.
Adding to 132114303311310 its reverse (13113303411231), we get a palindrome (145227606722541).
The spelling of 132114303311310 in words is "one hundred thirty-two trillion, one hundred fourteen billion, three hundred three million, three hundred eleven thousand, three hundred ten".
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