Base | Representation |
---|---|
bin | 11110000010100001001010… |
… | …011001001011100101000011 |
3 | 122022210000110121221012120121 |
4 | 132002201022121023211003 |
5 | 114304030334141434341 |
6 | 1144552311543121111 |
7 | 36553645015305424 |
oct | 3602411231134503 |
9 | 568700417835517 |
10 | 132114442139971 |
11 | 3910646940a685 |
12 | 129987b7443197 |
13 | 5894452712035 |
14 | 248a531b9964b |
15 | 10418ee62d4d1 |
hex | 78284a64b943 |
132114442139971 has 2 divisors, whose sum is σ = 132114442139972. Its totient is φ = 132114442139970.
The previous prime is 132114442139959. The next prime is 132114442139983. The reversal of 132114442139971 is 179931244411231.
It is a balanced prime because it is at equal distance from previous prime (132114442139959) and next prime (132114442139983).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132114442139971 is a prime.
It is not a weakly prime, because it can be changed into another prime (132114442139671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66057221069985 + 66057221069986.
It is an arithmetic number, because the mean of its divisors is an integer number (66057221069986).
Almost surely, 2132114442139971 is an apocalyptic number.
132114442139971 is a deficient number, since it is larger than the sum of its proper divisors (1).
132114442139971 is an equidigital number, since it uses as much as digits as its factorization.
132114442139971 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1306368, while the sum is 52.
The spelling of 132114442139971 in words is "one hundred thirty-two trillion, one hundred fourteen billion, four hundred forty-two million, one hundred thirty-nine thousand, nine hundred seventy-one".
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