Base | Representation |
---|---|
bin | 10011001110011110011… |
… | …111100001101011010011 |
3 | 11200022021200021112212200 |
4 | 103032132133201223103 |
5 | 133121321242240103 |
6 | 2450542441454243 |
7 | 164311625624130 |
oct | 23163637415323 |
9 | 4608250245780 |
10 | 1321214024403 |
11 | 46a361966769 |
12 | 194087aa1383 |
13 | 97789166ac0 |
14 | 47d38bb1587 |
15 | 2457b54c0a3 |
hex | 1339e7e1ad3 |
1321214024403 has 48 divisors (see below), whose sum is σ = 2378557009920. Its totient is φ = 688082496192.
The previous prime is 1321214024369. The next prime is 1321214024411. The reversal of 1321214024403 is 3044204121231.
1321214024403 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 214 + 0 + 2 + 440 + 3 = 666.
It is not a de Polignac number, because 1321214024403 - 29 = 1321214023891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1321214024203) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10145451 + ... + 10274852.
It is an arithmetic number, because the mean of its divisors is an integer number (49553271040).
Almost surely, 21321214024403 is an apocalyptic number.
1321214024403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1321214024403 is a deficient number, since it is larger than the sum of its proper divisors (1057342985517).
1321214024403 is a wasteful number, since it uses less digits than its factorization.
1321214024403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20420408 (or 20420405 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 1321214024403 its reverse (3044204121231), we get a palindrome (4365418145634).
The spelling of 1321214024403 in words is "one trillion, three hundred twenty-one billion, two hundred fourteen million, twenty-four thousand, four hundred three".
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