Base | Representation |
---|---|
bin | 1100000001000011010101… |
… | …0110001001110110010111 |
3 | 1201210002000221100011000000 |
4 | 3000100311112021312113 |
5 | 3212432103341334310 |
6 | 44033335115422343 |
7 | 2532356663303235 |
oct | 300206526116627 |
9 | 51702027304000 |
10 | 13212214402455 |
11 | 42342a5652282 |
12 | 1594747a549b3 |
13 | 74aba2699a63 |
14 | 3396903b5955 |
15 | 17da300cd4c0 |
hex | c0435589d97 |
13212214402455 has 112 divisors (see below), whose sum is σ = 23914831430880. Its totient is φ = 7003947896064.
The previous prime is 13212214402423. The next prime is 13212214402477. The reversal of 13212214402455 is 55420441221231.
13212214402455 is a `hidden beast` number, since 1 + 3 + 21 + 221 + 4 + 402 + 4 + 5 + 5 = 666.
It is not a de Polignac number, because 13212214402455 - 25 = 13212214402423 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 2320779589 + ... + 2320785281.
Almost surely, 213212214402455 is an apocalyptic number.
13212214402455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13212214402455 is a deficient number, since it is larger than the sum of its proper divisors (10702617028425).
13212214402455 is an equidigital number, since it uses as much as digits as its factorization.
13212214402455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9452 (or 9437 counting only the distinct ones).
The product of its (nonzero) digits is 76800, while the sum is 36.
Adding to 13212214402455 its reverse (55420441221231), we get a palindrome (68632655623686).
The spelling of 13212214402455 in words is "thirteen trillion, two hundred twelve billion, two hundred fourteen million, four hundred two thousand, four hundred fifty-five".
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