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132122412431 is a prime number
BaseRepresentation
bin111101100001100011…
…1000000010110001111
3110122000211121222010122
41323003013000112033
54131041314144211
6140410213455155
712355054655462
oct1730307002617
9418024558118
10132122412431
115103a725a99
12217336414bb
13c5c780bb89
14657530b2d9
1536843566db
hex1ec31c058f

132122412431 has 2 divisors, whose sum is σ = 132122412432. Its totient is φ = 132122412430.

The previous prime is 132122412413. The next prime is 132122412451. The reversal of 132122412431 is 134214221231.

It is a happy number.

Together with previous prime (132122412413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132122412431 - 218 = 132122150287 is a prime.

It is a super-2 number, since 2×1321224124312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132122412431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132122412451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66061206215 + 66061206216.

It is an arithmetic number, because the mean of its divisors is an integer number (66061206216).

Almost surely, 2132122412431 is an apocalyptic number.

132122412431 is a deficient number, since it is larger than the sum of its proper divisors (1).

132122412431 is an equidigital number, since it uses as much as digits as its factorization.

132122412431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2304, while the sum is 26.

Adding to 132122412431 its reverse (134214221231), we get a palindrome (266336633662).

The spelling of 132122412431 in words is "one hundred thirty-two billion, one hundred twenty-two million, four hundred twelve thousand, four hundred thirty-one".