Base | Representation |
---|---|
bin | 1100000001000011011110… |
… | …1110011010001000011011 |
3 | 1201210002010201102220202201 |
4 | 3000100313232122020123 |
5 | 3212432144101040120 |
6 | 44033343103111031 |
7 | 2532360656455366 |
oct | 300206756321033 |
9 | 51702121386681 |
10 | 13212254315035 |
11 | 4234316133186 |
12 | 15947592a2477 |
13 | 74abaaa32879 |
14 | 3396958050dd |
15 | 17da3386440a |
hex | c0437b9a21b |
13212254315035 has 4 divisors (see below), whose sum is σ = 15854705178048. Its totient is φ = 10569803452024.
The previous prime is 13212254315027. The next prime is 13212254315047. The reversal of 13212254315035 is 53051345221231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13212254315035 - 23 = 13212254315027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13212254314985 and 13212254315003.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1321225431499 + ... + 1321225431508.
It is an arithmetic number, because the mean of its divisors is an integer number (3963676294512).
Almost surely, 213212254315035 is an apocalyptic number.
13212254315035 is a deficient number, since it is larger than the sum of its proper divisors (2642450863013).
13212254315035 is an equidigital number, since it uses as much as digits as its factorization.
13212254315035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2642450863012.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 13212254315035 its reverse (53051345221231), we get a palindrome (66263599536266).
The spelling of 13212254315035 in words is "thirteen trillion, two hundred twelve billion, two hundred fifty-four million, three hundred fifteen thousand, thirty-five".
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