Base | Representation |
---|---|
bin | 11000100111000010… |
… | …10110110101110111 |
3 | 1021002210111010201212 |
4 | 30103201112311313 |
5 | 204024334211203 |
6 | 10023015512035 |
7 | 645262442255 |
oct | 142341266567 |
9 | 37083433655 |
10 | 13212413303 |
11 | 5670076741 |
12 | 268898861b |
13 | 13273b414b |
14 | 8d4a5d5d5 |
15 | 524e0e1d8 |
hex | 313856d77 |
13212413303 has 4 divisors (see below), whose sum is σ = 13534667328. Its totient is φ = 12890159280.
The previous prime is 13212413297. The next prime is 13212413317. The reversal of 13212413303 is 30331421231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13212413303 - 214 = 13212396919 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13212413353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161126951 + ... + 161127032.
It is an arithmetic number, because the mean of its divisors is an integer number (3383666832).
Almost surely, 213212413303 is an apocalyptic number.
13212413303 is a deficient number, since it is larger than the sum of its proper divisors (322254025).
13212413303 is an equidigital number, since it uses as much as digits as its factorization.
13212413303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 322254024.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13212413303 its reverse (30331421231), we get a palindrome (43543834534).
The spelling of 13212413303 in words is "thirteen billion, two hundred twelve million, four hundred thirteen thousand, three hundred three".
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