Base | Representation |
---|---|
bin | 10011001110100000101… |
… | …110001101111001011111 |
3 | 11200022101021122221200112 |
4 | 103032200232031321133 |
5 | 133121410331224413 |
6 | 2450550255320235 |
7 | 164312561565242 |
oct | 23164056157137 |
9 | 4608337587615 |
10 | 1321251429983 |
11 | 46a380a95071 |
12 | 19409852007b |
13 | 97793b32794 |
14 | 47d3db4b259 |
15 | 2457e98a2a8 |
hex | 133a0b8de5f |
1321251429983 has 2 divisors, whose sum is σ = 1321251429984. Its totient is φ = 1321251429982.
The previous prime is 1321251429937. The next prime is 1321251430067. The reversal of 1321251429983 is 3899241521231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1321251429983 - 218 = 1321251167839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321251429923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660625714991 + 660625714992.
It is an arithmetic number, because the mean of its divisors is an integer number (660625714992).
Almost surely, 21321251429983 is an apocalyptic number.
1321251429983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321251429983 is an equidigital number, since it uses as much as digits as its factorization.
1321251429983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 933120, while the sum is 50.
The spelling of 1321251429983 in words is "one trillion, three hundred twenty-one billion, two hundred fifty-one million, four hundred twenty-nine thousand, nine hundred eighty-three".
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