Base | Representation |
---|---|
bin | 111101100001110100… |
… | …0111111010011011011 |
3 | 110122001110101120110112 |
4 | 1323003220333103123 |
5 | 4131101104233201 |
6 | 140411132434535 |
7 | 12355223461232 |
oct | 1730350772333 |
9 | 418043346415 |
10 | 132131321051 |
11 | 51044760194 |
12 | 21736618a4b |
13 | c5c960aa52 |
14 | 6576589b19 |
15 | 36850160bb |
hex | 1ec3a3f4db |
132131321051 has 2 divisors, whose sum is σ = 132131321052. Its totient is φ = 132131321050.
The previous prime is 132131321009. The next prime is 132131321053. The reversal of 132131321051 is 150123131231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132131321051 is a prime.
Together with 132131321053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132131321053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66065660525 + 66065660526.
It is an arithmetic number, because the mean of its divisors is an integer number (66065660526).
Almost surely, 2132131321051 is an apocalyptic number.
132131321051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132131321051 is an equidigital number, since it uses as much as digits as its factorization.
132131321051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 132131321051 its reverse (150123131231), we get a palindrome (282254452282).
The spelling of 132131321051 in words is "one hundred thirty-two billion, one hundred thirty-one million, three hundred twenty-one thousand, fifty-one".
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