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1321320041 is a prime number
BaseRepresentation
bin100111011000001…
…1011111001101001
310102002022000100022
41032300123321221
510201224220131
6335040250225
744513015006
oct11660337151
93362260308
101321320041
1161893a338
1230a610975
131809911a2
14c76b08ad
157b00237b
hex4ec1be69

1321320041 has 2 divisors, whose sum is σ = 1321320042. Its totient is φ = 1321320040.

The previous prime is 1321319981. The next prime is 1321320043. The reversal of 1321320041 is 1400231231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1296360025 + 24960016 = 36005^2 + 4996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1321320041 is a prime.

It is a Sophie Germain prime.

Together with 1321320043, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1321320043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660660020 + 660660021.

It is an arithmetic number, because the mean of its divisors is an integer number (660660021).

Almost surely, 21321320041 is an apocalyptic number.

It is an amenable number.

1321320041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321320041 is an equidigital number, since it uses as much as digits as its factorization.

1321320041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1321320041 is about 36349.9661760503. The cubic root of 1321320041 is about 1097.3268537896.

Adding to 1321320041 its reverse (1400231231), we get a palindrome (2721551272).

The spelling of 1321320041 in words is "one billion, three hundred twenty-one million, three hundred twenty thousand, forty-one".