Base | Representation |
---|---|
bin | 11110000010110001100001… |
… | …101001010011000011110111 |
3 | 122022211200211002221011110221 |
4 | 132002301201221103003313 |
5 | 114304322330100010241 |
6 | 1145004335224355211 |
7 | 36555136302504151 |
oct | 3602614151230367 |
9 | 568750732834427 |
10 | 132132012110071 |
11 | 39112965186226 |
12 | 129a009b615b07 |
13 | 5895cc281854c |
14 | 248b31b445ad1 |
15 | 10420cbd905d1 |
hex | 782c61a530f7 |
132132012110071 has 2 divisors, whose sum is σ = 132132012110072. Its totient is φ = 132132012110070.
The previous prime is 132132012109967. The next prime is 132132012110099. The reversal of 132132012110071 is 170011210231231.
It is a strong prime.
It is an emirp because it is prime and its reverse (170011210231231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132132012110071 - 213 = 132132012101879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132132012110471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66066006055035 + 66066006055036.
It is an arithmetic number, because the mean of its divisors is an integer number (66066006055036).
Almost surely, 2132132012110071 is an apocalyptic number.
132132012110071 is a deficient number, since it is larger than the sum of its proper divisors (1).
132132012110071 is an equidigital number, since it uses as much as digits as its factorization.
132132012110071 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 25.
The spelling of 132132012110071 in words is "one hundred thirty-two trillion, one hundred thirty-two billion, twelve million, one hundred ten thousand, seventy-one".
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