Base | Representation |
---|---|
bin | 11110000010110010111000… |
… | …001101000101001111011111 |
3 | 122022211211120022112122101211 |
4 | 132002302320031011033133 |
5 | 114304333313332044411 |
6 | 1145005135302445251 |
7 | 36555220265255116 |
oct | 3602627015051737 |
9 | 568754508478354 |
10 | 132133464331231 |
11 | 3911353a9a2500 |
12 | 129a0425a33827 |
13 | 589619464c3cc |
14 | 248b41826cc7d |
15 | 10421645ed221 |
hex | 782cb83453df |
132133464331231 has 24 divisors (see below), whose sum is σ = 148625577309440. Its totient is φ = 117319641682320.
The previous prime is 132133464331229. The next prime is 132133464331249.
132133464331231 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 132133464331231 - 21 = 132133464331229 is a prime.
It is a super-2 number, since 2×1321334643312312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132133464331201) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 74457256 + ... + 76211218.
Almost surely, 2132133464331231 is an apocalyptic number.
132133464331231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132133464331231 is a deficient number, since it is larger than the sum of its proper divisors (16492112978209).
132133464331231 is a wasteful number, since it uses less digits than its factorization.
132133464331231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1768507 (or 1768496 counting only the distinct ones).
The product of its digits is 279936, while the sum is 40.
The spelling of 132133464331231 in words is "one hundred thirty-two trillion, one hundred thirty-three billion, four hundred sixty-four million, three hundred thirty-one thousand, two hundred thirty-one".
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