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132135320045342 = 2312131214839441
BaseRepresentation
bin11110000010110100100110…
…110100000100011100011110
3122022212000100122101200121002
4132002310212310010130132
5114304401113412422332
61145010043353110302
736555314260466255
oct3602644664043436
9568760318350532
10132135320045342
113911430244aa29
12129a08633b8392
1358963cbc486b3
14248b5528c979c
1510422224ae562
hex782d26d0471e

132135320045342 has 8 divisors (see below), whose sum is σ = 204596624586432. Its totient is φ = 63936445183200.

The previous prime is 132135320045329. The next prime is 132135320045347. The reversal of 132135320045342 is 243540023531231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 132135320045296 and 132135320045305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132135320045347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1065607419659 + ... + 1065607419782.

It is an arithmetic number, because the mean of its divisors is an integer number (25574578073304).

Almost surely, 2132135320045342 is an apocalyptic number.

132135320045342 is a deficient number, since it is larger than the sum of its proper divisors (72461304541090).

132135320045342 is a wasteful number, since it uses less digits than its factorization.

132135320045342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2131214839474.

The product of its (nonzero) digits is 259200, while the sum is 38.

Adding to 132135320045342 its reverse (243540023531231), we get a palindrome (375675343576573).

The spelling of 132135320045342 in words is "one hundred thirty-two trillion, one hundred thirty-five billion, three hundred twenty million, forty-five thousand, three hundred forty-two".

Divisors: 1 2 31 62 2131214839441 4262429678882 66067660022671 132135320045342