Base | Representation |
---|---|
bin | 111101100010000111… |
… | …0101000010000110011 |
3 | 110122002010221212120112 |
4 | 1323010032220100303 |
5 | 4131111121010042 |
6 | 140412124131535 |
7 | 12355403365253 |
oct | 1730416502063 |
9 | 418063855515 |
10 | 132141188147 |
11 | 5104a28a511 |
12 | 21739996bab |
13 | c5cb683c77 |
14 | 65779d7963 |
15 | 3685d14982 |
hex | 1ec43a8433 |
132141188147 has 2 divisors, whose sum is σ = 132141188148. Its totient is φ = 132141188146.
The previous prime is 132141188117. The next prime is 132141188177. The reversal of 132141188147 is 741881141231.
It is a balanced prime because it is at equal distance from previous prime (132141188117) and next prime (132141188177).
It is a cyclic number.
It is not a de Polignac number, because 132141188147 - 216 = 132141122611 is a prime.
It is a super-2 number, since 2×1321411881472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132141188107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66070594073 + 66070594074.
It is an arithmetic number, because the mean of its divisors is an integer number (66070594074).
Almost surely, 2132141188147 is an apocalyptic number.
132141188147 is a deficient number, since it is larger than the sum of its proper divisors (1).
132141188147 is an equidigital number, since it uses as much as digits as its factorization.
132141188147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 43008, while the sum is 41.
The spelling of 132141188147 in words is "one hundred thirty-two billion, one hundred forty-one million, one hundred eighty-eight thousand, one hundred forty-seven".
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