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1321415341469 is a prime number
BaseRepresentation
bin10011001110101010011…
…111011111010110011101
311200022210201002111222022
4103032222133133112131
5133122224311411334
62451014432425525
7164316622035266
oct23165237372635
94608721074868
101321415341469
1146a455569203
121941233a82a5
13977bba92722
1447d5781796d
152458e06682e
hex133aa7df59d

1321415341469 has 2 divisors, whose sum is σ = 1321415341470. Its totient is φ = 1321415341468.

The previous prime is 1321415341429. The next prime is 1321415341471. The reversal of 1321415341469 is 9641435141231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1087928269444 + 233487072025 = 1043038^2 + 483205^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1321415341469 is a prime.

It is a super-2 number, since 2×13214153414692 (a number of 25 digits) contains 22 as substring.

Together with 1321415341471, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1321415341409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660707670734 + 660707670735.

It is an arithmetic number, because the mean of its divisors is an integer number (660707670735).

Almost surely, 21321415341469 is an apocalyptic number.

It is an amenable number.

1321415341469 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321415341469 is an equidigital number, since it uses as much as digits as its factorization.

1321415341469 is an evil number, because the sum of its binary digits is even.

The product of its digits is 311040, while the sum is 44.

The spelling of 1321415341469 in words is "one trillion, three hundred twenty-one billion, four hundred fifteen million, three hundred forty-one thousand, four hundred sixty-nine".