13214211241231 has 16 divisors (see below), whose sum is σ = 17742157751808. Its totient is φ = 9504727365600.

The previous prime is 13214211241171. The next prime is 13214211241279.

13214211241231 is nontrivially palindromic in base 10.

13214211241231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13214211241231 - 2¹¹ = 13214211239183 is a prime.

It is a super-3 number, since 3×13214211241231³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 13214211241231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13214211245231) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6600504115 + ... + 6600506116.

It is an arithmetic number, because the mean of its divisors is an integer number (1108884859488).

Almost surely, 2^{13214211241231} is an apocalyptic number.

13214211241231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13214211241231 is a deficient number, since it is larger than the sum of its proper divisors (4527946510577).

13214211241231 is a wasteful number, since it uses less digits than its factorization.

13214211241231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13201010262.

The product of its digits is 2304, while the sum is 28.

It can be divided in two parts, 1321421 and 1241231, that added together give a palindrome (2562652).

The spelling of 13214211241231 in words is "thirteen trillion, two hundred fourteen billion, two hundred eleven million, two hundred forty-one thousand, two hundred thirty-one".