Base | Representation |
---|---|
bin | 1100000001001010111010… |
… | …1111101010111001010000 |
3 | 1201210021021212210212011211 |
4 | 3000102232233222321100 |
5 | 3213000241242301134 |
6 | 44034313153545504 |
7 | 2532461314242535 |
oct | 300225657527120 |
9 | 51707255725154 |
10 | 13214251134544 |
11 | 42351502a8239 |
12 | 1595015b75294 |
13 | 74b138635385 |
14 | 339804ab2d8c |
15 | 17daedce9764 |
hex | c04aebeae50 |
13214251134544 has 10 divisors (see below), whose sum is σ = 25602611573210. Its totient is φ = 6607125567264.
The previous prime is 13214251134527. The next prime is 13214251134629. The reversal of 13214251134544 is 44543115241231.
It can be written as a sum of positive squares in only one way, i.e., 12152279664144 + 1061971470400 = 3486012^2 + 1030520^2 .
It is a junction number, because it is equal to n+sod(n) for n = 13214251134497 and 13214251134506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 412945347939 + ... + 412945347970.
It is an arithmetic number, because the mean of its divisors is an integer number (2560261157321).
Almost surely, 213214251134544 is an apocalyptic number.
It is an amenable number.
13214251134544 is a deficient number, since it is larger than the sum of its proper divisors (12388360438666).
13214251134544 is an equidigital number, since it uses as much as digits as its factorization.
13214251134544 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 825890695917 (or 825890695911 counting only the distinct ones).
The product of its digits is 230400, while the sum is 40.
Adding to 13214251134544 its reverse (44543115241231), we get a palindrome (57757366375775).
The spelling of 13214251134544 in words is "thirteen trillion, two hundred fourteen billion, two hundred fifty-one million, one hundred thirty-four thousand, five hundred forty-four".
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