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1321434211053 = 31123640314631
BaseRepresentation
bin10011001110101011100…
…111011110001011101101
311200022212000121012011210
4103032223213132023231
5133122244124223203
62451020345105033
7164320241315535
oct23165347361355
94608760535153
101321434211053
1146a465187200
12194129788179
13977c296b468
1447d5a12a4c5
1524590a42803
hex133ab9de2ed

1321434211053 has 12 divisors (see below), whose sum is σ = 1936647384224. Its totient is φ = 800869218600.

The previous prime is 1321434211049. The next prime is 1321434211067. The reversal of 1321434211053 is 3501124341231.

It is not a de Polignac number, because 1321434211053 - 22 = 1321434211049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1321434211053.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1321434211033) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1820156953 + ... + 1820157678.

Almost surely, 21321434211053 is an apocalyptic number.

It is an amenable number.

1321434211053 is a deficient number, since it is larger than the sum of its proper divisors (615213173171).

1321434211053 is a wasteful number, since it uses less digits than its factorization.

1321434211053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3640314656 (or 3640314645 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 1321434211053 its reverse (3501124341231), we get a palindrome (4822558552284).

The spelling of 1321434211053 in words is "one trillion, three hundred twenty-one billion, four hundred thirty-four million, two hundred eleven thousand, fifty-three".

Divisors: 1 3 11 33 121 363 3640314631 10920943893 40043460941 120130382823 440478070351 1321434211053