Base | Representation |
---|---|
bin | 1100000001001011011110… |
… | …1101011110001101100111 |
3 | 1201210021200100211220212012 |
4 | 3000102313231132031213 |
5 | 3213001043244201010 |
6 | 44034340125544435 |
7 | 2532465121625210 |
oct | 300226755361547 |
9 | 51707610756765 |
10 | 13214401553255 |
11 | 42352181a6021 |
12 | 159505841511b |
13 | 74b16084ca26 |
14 | 33981aa6a407 |
15 | 17db0c10d005 |
hex | c04b7b5e367 |
13214401553255 has 8 divisors (see below), whose sum is σ = 18122607844512. Its totient is φ = 9061303922208.
The previous prime is 13214401553251. The next prime is 13214401553261. The reversal of 13214401553255 is 55235510441231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13214401553255 - 22 = 13214401553251 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13214401553251) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 188777165012 + ... + 188777165081.
It is an arithmetic number, because the mean of its divisors is an integer number (2265325980564).
Almost surely, 213214401553255 is an apocalyptic number.
13214401553255 is a deficient number, since it is larger than the sum of its proper divisors (4908206291257).
13214401553255 is an equidigital number, since it uses as much as digits as its factorization.
13214401553255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 377554330105.
The product of its (nonzero) digits is 360000, while the sum is 41.
Adding to 13214401553255 its reverse (55235510441231), we get a palindrome (68449911994486).
The spelling of 13214401553255 in words is "thirteen trillion, two hundred fourteen billion, four hundred one million, five hundred fifty-three thousand, two hundred fifty-five".
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