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132144324155143 is a prime number
BaseRepresentation
bin11110000010111100111111…
…100000000001011100000111
3122022212212121011012212012021
4132002330333200001130013
5114310023033440431033
61145014133042304011
736556053353245246
oct3602747740013407
9568785534185167
10132144324155143
1139118102a98993
12129a2556958007
135897205507511
14248bb6869095d
15104259cbedb2d
hex782f3f801707

132144324155143 has 2 divisors, whose sum is σ = 132144324155144. Its totient is φ = 132144324155142.

The previous prime is 132144324155117. The next prime is 132144324155149. The reversal of 132144324155143 is 341551423441231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132144324155143 - 217 = 132144324024071 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132144324155143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132144324155149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66072162077571 + 66072162077572.

It is an arithmetic number, because the mean of its divisors is an integer number (66072162077572).

Almost surely, 2132144324155143 is an apocalyptic number.

132144324155143 is a deficient number, since it is larger than the sum of its proper divisors (1).

132144324155143 is an equidigital number, since it uses as much as digits as its factorization.

132144324155143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 691200, while the sum is 43.

Adding to 132144324155143 its reverse (341551423441231), we get a palindrome (473695747596374).

The spelling of 132144324155143 in words is "one hundred thirty-two trillion, one hundred forty-four billion, three hundred twenty-four million, one hundred fifty-five thousand, one hundred forty-three".