Base | Representation |
---|---|
bin | 1100000001001011100110… |
… | …0101011110100110000111 |
3 | 1201210021202120001012021201 |
4 | 3000102321211132212013 |
5 | 3213001124322341403 |
6 | 44034343212123331 |
7 | 2532465653211031 |
oct | 300227145364607 |
9 | 51707676035251 |
10 | 13214433012103 |
11 | 4235233a32574 |
12 | 1595066a66547 |
13 | 74b167215a2b |
14 | 339820cd8c51 |
15 | 17db0ec7421d |
hex | c04b995e987 |
13214433012103 has 2 divisors, whose sum is σ = 13214433012104. Its totient is φ = 13214433012102.
The previous prime is 13214433012101. The next prime is 13214433012127. The reversal of 13214433012103 is 30121033441231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13214433012103 - 21 = 13214433012101 is a prime.
Together with 13214433012101, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13214433012101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607216506051 + 6607216506052.
It is an arithmetic number, because the mean of its divisors is an integer number (6607216506052).
Almost surely, 213214433012103 is an apocalyptic number.
13214433012103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13214433012103 is an equidigital number, since it uses as much as digits as its factorization.
13214433012103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13214433012103 its reverse (30121033441231), we get a palindrome (43335466453334).
The spelling of 13214433012103 in words is "thirteen trillion, two hundred fourteen billion, four hundred thirty-three million, twelve thousand, one hundred three".
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