1321443342140 has 12 divisors (see below), whose sum is σ = 2775031018536. Its totient is φ = 528577336848.

The previous prime is 1321443342137. The next prime is 1321443342223. The reversal of 1321443342140 is 412433441231.

It is a super-2 number, since 2×1321443342140² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1321443342097 and 1321443342106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33036083534 + ... + 33036083573.

It is an arithmetic number, because the mean of its divisors is an integer number (231252584878).

Almost surely, 2^{1321443342140} is an apocalyptic number.

1321443342140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1321443342140 is an abundant number, since it is smaller than the sum of its proper divisors (1453587676396).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1321443342140 is a wasteful number, since it uses less digits than its factorization.

1321443342140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66072167116 (or 66072167114 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 1321443342140 its reverse (412433441231), we get a palindrome (1733876783371).

Subtracting from 1321443342140 its reverse (412433441231), we obtain a palindrome (909009900909).

The spelling of 1321443342140 in words is "one trillion, three hundred twenty-one billion, four hundred forty-three million, three hundred forty-two thousand, one hundred forty".