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13214465421341 = 17777321495373
BaseRepresentation
bin1100000001001011101110…
…0001000111000000011101
31201210021211211000202101212
43000102323201013000131
53213001211121440331
644034350330514205
72532466525532432
oct300227341070035
951707754022355
1013214465421341
114235250259068
121595075895965
1374b170b524b2
14339825333b89
1517db12a26d2b
hexc04bb84701d

13214465421341 has 4 divisors (see below), whose sum is σ = 13991786916732. Its totient is φ = 12437143925952.

The previous prime is 13214465421337. The next prime is 13214465421359. The reversal of 13214465421341 is 14312456441231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12015339679225 + 1199125742116 = 3466315^2 + 1095046^2 .

It is a cyclic number.

It is not a de Polignac number, because 13214465421341 - 22 = 13214465421337 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13214465421301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388660747670 + ... + 388660747703.

It is an arithmetic number, because the mean of its divisors is an integer number (3497946729183).

Almost surely, 213214465421341 is an apocalyptic number.

It is an amenable number.

13214465421341 is a deficient number, since it is larger than the sum of its proper divisors (777321495391).

13214465421341 is an equidigital number, since it uses as much as digits as its factorization.

13214465421341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 777321495390.

The product of its digits is 276480, while the sum is 41.

The spelling of 13214465421341 in words is "thirteen trillion, two hundred fourteen billion, four hundred sixty-five million, four hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 17 777321495373 13214465421341